Files
help/source/text/sbasic/shared/03140000.xhp
Ilmari Lauhakangas 7e42394ecb tdf#152323 drop name attribute from <link> elements
Replacement done with

find . -name \*.xhp -print0 |xargs -0 -P 0 perl -CS -pi -e \
        's#(<link[^>]*?) +name *="[^"]*" *( [^>]+|) *>#$1$2>#g'

(note some inconsistencies with space between name and = and also having
empty value, and some more complicated expression to also clear up
double space before/after the attribute)

translation files will be prepped with:

find */helpcontent2 -name \*.po -print0 |xargs -0 -P 0 perl -CS -pi -e \
    $'s#(<link[^>]*?) +name=(?:\\\\"[^"]*\\\\"|\'[^\']*\') *( [^>]+|) *(/?>)#$1$2$3#g unless /^#/'

(note that not all languages use the " as quote character for the
attributes, but that also single quotes appera in the po file. Hence
the use of the shell $'string' syntax to be able to quote ' as \'
It also requires to quote the backslash, so that it needs to be escaped
once for the shell, then another time for perl. Also don't work on
obsolete strings (those are prefixed with #~ in the po files)
Also note that <link..></link> gets turned into <link ../> during
translation extraction (along with removal of the space between the
attribute name and the value), so the pattern needs to be slightly
different here)

Change-Id: I95e53a08e6b0095cd894109ea0de154cc4859d8f
Reviewed-on: https://gerrit.libreoffice.org/c/help/+/143713
Tested-by: Jenkins
Reviewed-by: Christian Lohmaier <lohmaier+LibreOffice@googlemail.com>
2022-12-07 17:39:02 +00:00

71 lines
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XML

<?xml version="1.0" encoding="UTF-8"?>
<helpdocument version="1.0">
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<meta>
<topic id="textsbasicshared03140000xml" indexer="include" status="PUBLISH">
<title id="tit" xml-lang="en-US">DDB Function [VBA]</title>
<filename>/text/sbasic/shared/03140000.xhp</filename>
</topic>
</meta>
<body>
<section id="ddb">
<bookmark xml-lang="en-US" branch="index" id="bm_id3150499">
<bookmark_value>DDB function</bookmark_value>
</bookmark>
<paragraph id="hd_id3150499" role="heading" level="1" xml-lang="en-US"><link href="text/sbasic/shared/03140000.xhp">DDB Function [VBA]</link></paragraph>
<paragraph id="par_id3151384" role="paragraph" xml-lang="en-US">Returns the depreciation of an asset for a specified period using the arithmetic-declining method.</paragraph>
</section>
<embed href="text/sbasic/shared/00000003.xhp#vbasupport"/>
<embed href="text/sbasic/shared/00000003.xhp#functsyntax"/>
<bascode>
<paragraph id="par_id3143267" role="bascode" localize="false" xml-lang="en-US">DDB(Cost As Double, Salvage As Double, Life as Double, Period as Double, [Factor as Variant])</paragraph>
</bascode>
<embed href="text/sbasic/shared/00000003.xhp#functvalue"/>
<paragraph id="par_id3150669" role="paragraph" localize="false" xml-lang="en-US">Double</paragraph>
<embed href="text/sbasic/shared/00000003.xhp#functparameters"/>
<paragraph id="par_id061420170142332738" role="paragraph" xml-lang="en-US"><emph>Cost</emph> fixes the initial cost of an asset.</paragraph>
<paragraph id="par_id061420170142331999" role="paragraph" xml-lang="en-US"><emph>Salvage</emph> fixes the value of an asset at the end of its life.</paragraph>
<paragraph id="par_id061420170142338147" role="paragraph" xml-lang="en-US"><emph>Life</emph> is the number of periods (for example, years or months) defining how long the asset is to be used.</paragraph>
<paragraph id="par_id061420170142338917" role="paragraph" xml-lang="en-US"><emph>Period</emph> states the period for which the value is to be calculated.</paragraph>
<paragraph id="par_id061420170142335816" role="paragraph" xml-lang="en-US"><emph>Factor</emph> (optional) is the factor by which depreciation decreases. If a value is not entered, the default is factor 2.</paragraph>
<paragraph id="par_id3145609" role="paragraph" xml-lang="en-US">Use this form of depreciation if you require a higher initial depreciation value as opposed to linear depreciation. The depreciation value gets less with each period and is usually used for assets whose value loss is higher shortly after purchase (for example, vehicles, computers). Please note that the book value will never reach zero under this calculation type.</paragraph>
<embed href="text/sbasic/shared/00000003.xhp#errorcode"/>
<embed href="text/sbasic/shared/00000003.xhp#err5"/>
<embed href="text/sbasic/shared/00000003.xhp#functexample"/>
<bascode>
<paragraph id="par_id061420170142119551" role="bascode" localize="false" xml-lang="en-US">Sub ExampleDDB</paragraph>
<paragraph id="par_id061420170142169416" role="bascode" localize="false" xml-lang="en-US"> Dim ddb_yr1 As Double</paragraph>
<paragraph id="par_id06142017014218316" role="bascode" localize="false" xml-lang="en-US"> ddb_yr1 = DDB(75000,1,60,12,2)</paragraph>
<paragraph id="par_id061420170142332315" role="bascode" xml-lang="en-US"> Print ddb_yr1 ' returns 1,721.81 currency units. </paragraph>
<paragraph id="par_id061420170142255740" role="bascode" localize="false" xml-lang="en-US">End Sub</paragraph>
</bascode>
<section id="relatedtopics">
<paragraph id="par_id061420170153186192" role="paragraph" xml-lang="en-US"><link href="text/scalc/01/04060103.xhp#bm_id3149998">DDB function in CALC</link></paragraph>
<embed href="text/sbasic/shared/00000003.xhp#VBA-Financial"/>
</section>
</body>
</helpdocument>