Optimize FindNaluIndices
We can add i by 3 even if it's not 001, because in any xx1 combination, 1 could not be part of start code. Bug: None Change-Id: Ica653d9e49b9f7c665027b9cf4453753c5fdd3ed Reviewed-on: https://webrtc-review.googlesource.com/c/src/+/159721 Commit-Queue: Kári Helgason <kthelgason@webrtc.org> Reviewed-by: Erik Språng <sprang@webrtc.org> Reviewed-by: Kári Helgason <kthelgason@webrtc.org> Reviewed-by: Tommi <tommi@webrtc.org> Cr-Commit-Position: refs/heads/master@{#30064}
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@ -27,22 +27,26 @@ std::vector<NaluIndex> FindNaluIndices(const uint8_t* buffer,
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if (buffer_size < kNaluShortStartSequenceSize)
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return sequences;
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static_assert(kNaluShortStartSequenceSize >= 2,
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"kNaluShortStartSequenceSize must be larger or equals to 2");
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const size_t end = buffer_size - kNaluShortStartSequenceSize;
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for (size_t i = 0; i < end;) {
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if (buffer[i + 2] > 1) {
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i += 3;
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} else if (buffer[i + 2] == 1 && buffer[i + 1] == 0 && buffer[i] == 0) {
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// We found a start sequence, now check if it was a 3 of 4 byte one.
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NaluIndex index = {i, i + 3, 0};
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if (index.start_offset > 0 && buffer[index.start_offset - 1] == 0)
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--index.start_offset;
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} else if (buffer[i + 2] == 1) {
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if (buffer[i + 1] == 0 && buffer[i] == 0) {
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// We found a start sequence, now check if it was a 3 of 4 byte one.
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NaluIndex index = {i, i + 3, 0};
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if (index.start_offset > 0 && buffer[index.start_offset - 1] == 0)
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--index.start_offset;
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// Update length of previous entry.
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auto it = sequences.rbegin();
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if (it != sequences.rend())
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it->payload_size = index.start_offset - it->payload_start_offset;
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// Update length of previous entry.
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auto it = sequences.rbegin();
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if (it != sequences.rend())
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it->payload_size = index.start_offset - it->payload_start_offset;
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sequences.push_back(index);
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sequences.push_back(index);
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}
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i += 3;
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} else {
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